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江西省八年级2023-2024学年新课标闯关卷（十）JX数学试卷答案

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分析本题是一个分类计数问题，若个位数字为0，若个位数字不为0，根据分类加法原理得到结果．

解答解：由题意知本题是一个分类计数问题，
若末位数字为0，前四位的排法种数为A₉⁴=3024，
若末位数字不为0，则确定末数字有4种方法，确定首位数字有8种方法，排法种数为4×8×A₈³=10752，
根据分类计数原理，可得3024+10752=13776，
故可以组成13776个没有重复数字的五位偶数．

点评本题考查排列组合及简单计数问题，本题解题的关键是看清楚对于数字0的特殊情况，在最后一位可以得到偶数又不能排在第一位．